dont type @, just .25<45
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How do i draw line at specific angle.
if i have the length on the x axis and angle,
when i do @.25<45 the line becomes .25 in length
i need the x dim to be .25 @ 45 degrees. as shown in the picture
dont type @, just .25<45
....always perform Beyond what is expected.
it wont accept
@,.25<45
i need the x dim to be .25
not the angular line
i mean dont include the @
just the .25<45
....always perform Beyond what is expected.
Check out the command line, the @ is automatically inputed anyway
....always perform Beyond what is expected.
first when i type .25<45 it wont put the @ automatic
second it will come absolute style
and third i need the .25 to be the x dim
not the angular dim (v). when i write it the way you said i get the (V) dim as .25
i need the x dim to be .25
Last edited by nbaryosef; 12th Oct 2008 at 06:54 am.
"first when i type .25<45 it wont put the @ automatic"
it is placed automatically after you hit enter, see the command line in my previous post.
as for your elusive question, its like drawing a right triangle where you want to draw a line(hypotenuse) where your input is based from the base angle and base length. No, there is no such way.
....always perform Beyond what is expected.
you may have to input using rectangular (cartesian) coordinates instead of polar, because when you use polar input, autocad interprets the first number as length, and not the x-component of the length.
if you want to use relative coordinates by default, with the @ symbol, then right-click on the "DYN" button and select settings. under "enable pointer input" select "settings", and then click on "relative coordinates".
In this particular case, knowing that 45° gives an equal x and y dimension, you should enter a relative coordinate of 0.25,0.25.
For polar coordinates, you should be inputting the hypotenuse (in this case 0.354), if you want to specify an angle.
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so there is no other way of doing it, the drawing i got had only the .25 dim
and the angle.
so what you tell me is that i need to find the other hight dim or find out the
the length of the hypotenuse (v) dim
thnks
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