How do i draw line at specific angle?

[nbaryosef]

How do i draw line at specific angle.

if i have the length on the x axis and angle,
when i do @.25<45 the line becomes .25 in length
i need the x dim to be .25 @ 45 degrees. as shown in the picture

[nocturne00]

dont type @, just .25<45

[nbaryosef]

it wont accept

@,.25<45

i need the x dim to be .25
not the angular line

[nocturne00]

i mean dont include the @
just the .25<45

[nocturne00]

Check out the command line, the @ is automatically inputed anyway

[nbaryosef]

first when i type .25<45 it wont put the @ automatic
second it will come absolute style
and third i need the .25 to be the x dim
not the angular dim (v). when i write it the way you said i get the (V) dim as .25
i need the x dim to be .25

[nocturne00]

"first when i type .25<45 it wont put the @ automatic"
it is placed automatically after you hit enter, see the command line in my previous post.
as for your elusive question, its like drawing a right triangle where you want to draw a line(hypotenuse) where your input is based from the base angle and base length. No, there is no such way.

[the ber]

you may have to input using rectangular (cartesian) coordinates instead of polar, because when you use polar input, autocad interprets the first number as length, and not the x-component of the length.
if you want to use relative coordinates by default, with the @ symbol, then right-click on the "DYN" button and select settings. under "enable pointer input" select "settings", and then click on "relative coordinates".

[eldon]

In this particular case, knowing that 45° gives an equal x and y dimension, you should enter a relative coordinate of 0.25,0.25.

For polar coordinates, you should be inputting the hypotenuse (in this case 0.354), if you want to specify an angle.

[nbaryosef]

so there is no other way of doing it, the drawing i got had only the .25 dim
and the angle.
so what you tell me is that i need to find the other hight dim or find out the
the length of the hypotenuse (v) dim

thnks