Select Polyline with variable ?

**rodrigo_sjc_sp** · 3rd Oct 2012 07:17 pm

I need select a Polyline with a variable,

This code is ok!
(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "First"))))

I need convert to:
(setq cod "Second")
(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . cod))))

But this code return
Command: ; error: bad SSGET list value

I need help to make this code.

Thanks
Rodrigo

**Tharwat** · 3rd Oct 2012 07:22 pm

The name of the layer should be string like the first line of code you brought .

Code:

(8 . "cod")

**Lee Mac** · 3rd Oct 2012 07:24 pm

http://www.cadtutor.net/forum/showpost.php?p=258390&postcount=20

**rodrigo_sjc_sp** · 3rd Oct 2012 07:27 pm

thank you ! =)

**Lee Mac** · 3rd Oct 2012 07:41 pm

You're welcome!

**rodrigo_sjc_sp** · 4th Oct 2012 01:43 pm

if i use

(setq valor "X1")
(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "valor"))))

The lisp does not recognize the value of the variable
If use variable with "" the lisp recognize VALOR and not X1

Any help?

**Tharwat** · 4th Oct 2012 01:47 pm

Originally Posted by rodrigo_sjc_sp

if i use

(setq valor "X1")
(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "valor"))))

The lisp does not recognize the value of the variable
If use variable with "" the lisp recognize VALOR and not X1

Any help?

Hola .

It should like this .

Code:

(setq valor "X1")
(setq selpline (ssget "_x" (list '(0 . "LWPOLYLINE")(cons 8 valor))))

**Lee Mac** · 4th Oct 2012 02:29 pm

Originally Posted by rodrigo_sjc_sp

if i use

(setq valor "X1")
(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "valor"))))

The lisp does not recognize the value of the variable
If use variable with "" the lisp recognize VALOR and not X1

Any help?

Did you read the post I linked to?

Thread: Select Polyline with variable ?

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