How to draw a circle so that a line becomes a tangent to it

Hi

This is my first question to this esteemed forum. I want asolution from the forum for the following problem.

I’ve an already drawn inclined line from a fixed point (saypoint (0,2) on Y-axis). The inclination is also fixed (say 150 tothe horizontal). My objective is to draw a circle with one quadrant at a fixedpoint (say point (1,0) on X-axis), so that, the line becomes a perfect tangentto the circle. The diameter of the circle may vary to make the line perfecttangent to the circle. How can I do it?

Thanks in advance

Surajit

In AutoCad you can use the Circle -> tan tan radius option

Can you please post a sketch of that case? I'm not able to understand it from your description - a line can be tangent on quadrant only to a horizontal or a vertical line, not a sloped one.

Reading twice your requirements, is this the case you were looking for?

If the above sketch is correct, then the formula of radius for the desired circle is:

Radius = Distance / (1 + Cosine(Angle))

• Distance means the distance from the given point to the given line.
  
• Angle is the angle made by the given line with X axis.
  

If I will have time later, will try to write you a routine for this.

Perhaps one of these:

Hi

Thanks for your replies. I'm sorry, I could not make you understand actually what I wanted. I'm enclosing an AutoCad drawing showing the sketch. The drawing is self explanatory.

I'm new to this forum. In attachment is not successful, kindly let me know.

Thanks

Surajit

Tangent to a circle.dwg

ah, that's clearer.

One way (may not be the best)

draw a vertical line through your fixed point.

mirror your angled line

CIRCLE 3P

tangent to one sloping line

select fixed point

tangent to other sloping line

Done.

So, it looks like Stefan's top version. Nice solution, Dave. It doesn't get much simpler than that!

Oh. that's great and so easy. Thanks:)