Vagulus Posted April 18, 2014 Share Posted April 18, 2014 This is the text-book exercise I am working on: Strictly speaking, the back of the jaw consists of two arcs and a tangent. I can't find anything in the book so far that deals with this so I am stuck. Can someone please help me out with a way to do the back of the jaw. Thanks BTW: as to the dimensions, I work in millimetres so I take the given imperial (inch) dimensions, multiply the number by 100, and call it mm. Hanger_Jaw.ipt Quote Link to comment Share on other sites More sharing options...
JD Mather Posted April 18, 2014 Share Posted April 18, 2014 You can always sketch a circle and trim. or sketch 3-point arcs or pro trick - when in the line command if you click hold and drag off off the endpoint of a line - Inventor automatically goes into creating an arc. Very handy, but takes some practice. Example 1 resembles the book. Note that two dimensions are not really needed and shown as (reference) dimensions. Example 2 is how I would really model the part. Hanger Jaw Example1.ipt Hanger Jaw Example2.ipt Quote Link to comment Share on other sites More sharing options...
JD Mather Posted April 18, 2014 Share Posted April 18, 2014 Strictly speaking, the back of the jaw consists of two arcs and a tangent. Strictly speaking, the back of the jaw consists of two arcs and 4 tangents. Quote Link to comment Share on other sites More sharing options...
Vagulus Posted April 18, 2014 Author Share Posted April 18, 2014 Strictly speaking, the back of the jaw consists of two arcs and 4 tangents. You are right, of course, about the four tangents, accepting that one is tangential to two arcs. I figured it could be done, and I see you have done it. What I can't figure out, and what is most use to me, is HOW you did it. Is there some way to infer this from the details in the Browser? Quote Link to comment Share on other sites More sharing options...
JD Mather Posted April 18, 2014 Share Posted April 18, 2014 .... What I can't figure out, and what is most use to me, is HOW you did it.Is there some way to infer this from the details in the Browser? See #14 here http://www.cadtutor.net/forum/showthread.php?85808-Inventor-101/page2 Quote Link to comment Share on other sites More sharing options...
JD Mather Posted April 18, 2014 Share Posted April 18, 2014 .... accepting that one is tangential to two arcs. All sketch constraints shown. Quote Link to comment Share on other sites More sharing options...
Vagulus Posted April 18, 2014 Author Share Posted April 18, 2014 http://www.cadtutor.net/forum/showthread.php?85808-Inventor-101/page2 That's SOME tutorial. I'll spend a few merry hours with that. Thanks Quote Link to comment Share on other sites More sharing options...
Vagulus Posted April 19, 2014 Author Share Posted April 19, 2014 All sketch constraints shown. Ah Hah! That's a million times quicker than the multiple extrusions I used. It's a great insight into the power of the primary sketch. Thanks once more! Quote Link to comment Share on other sites More sharing options...
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