Deby Ferdian Posted March 18, 2016 Share Posted March 18, 2016 (edited) How to create a line and Perpendicular or Parallel or Aligned to this one point that I create before. Without do move those both of that point ? I attach my result file of dwg so far this time til today I didn't.. -_-" How to create a line and Perpendicular or Parallel or Aligned to this one point that I create b.dwg ~.Sorry about my words. I am still beginner and I am also still process of learning in english.~ Edited March 18, 2016 by Deby Ferdian That have a less word I left to input supposed be! Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 (edited) Is this what you want to do? The yellow line is perpendicular to the sloped object. Or does the endpoint of the line have to be located at the node which for some strange reason has a thickness of .01? Like this... Edited March 18, 2016 by ReMark Quote Link to comment Share on other sites More sharing options...
Deby Ferdian Posted March 18, 2016 Author Share Posted March 18, 2016 No, but the line on the left that has stood upright and white and thick! Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 So you want to move the white line to the node and you want to make it perpendicular to the slope like my yellow line in the second image? Not sure there is any benefit to having lineweight enabled while working in 3D. Quote Link to comment Share on other sites More sharing options...
Deby Ferdian Posted March 18, 2016 Author Share Posted March 18, 2016 My intention is to make a thick white line that remained there and stand upright on the left side of the points above and adjusting the length of the line to the height of the solid object .. Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 Then rotate the line and change its length using any one of a couple of methods. What's so difficult about that? You don't need the second node at the peak of the slope. Quote Link to comment Share on other sites More sharing options...
Deby Ferdian Posted March 18, 2016 Author Share Posted March 18, 2016 From these two points it is the result of mine or what I thought or do about it but the results stated I do not get any results from it. My second aim is after the line is made of the same length with a high solid object that is so I can calculate the height. In conclusion; make the line by adjusting the height and produces high calculation line of solid objects. #sorry if I have do a mistake about my words or sentences and then so it makes you to hard to got me or understanding my speaks.. Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 You are right....I have no idea what you just said. Is the line in my last image in the correct location? Yes or no? Is the line shown in the correct orientation? Yes or no? Quote Link to comment Share on other sites More sharing options...
Deby Ferdian Posted March 18, 2016 Author Share Posted March 18, 2016 (edited) The location is true very well.. But the position I mean orientation supposed be stay in stood as an orthographically. Just only the length/long/height of the line that have to be adjusted.. This is my further try that has been completely done could be this good idea but still will be difficult way in some case.. May be you have a simply way then me @ReMark or any one else ? Edited March 18, 2016 by Deby Ferdian too many views of the pict! Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 I just love it when people don't make an attempt to answer my questions when I am trying to help them. I guess we just continue to play 20 questions. You want the white line to be the same height as the node at the peak of the fold? Yes or no? If the answer is yes then one option is to use math to calculate the difference in height of the two nodes. If the line has not been drawn yet you now have its length. If the line has already been drawn but it is the wrong length then use the LENGTHEN command to adjust the height or change its length in Quick Properties or Properties. Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 The yellow line is 1.9219 units in height. The top of the line is even with Node 2. How the height was calculated. I used the LIST command to get the "Z" coordinates for Node 1 and Node 2 and calculated the difference. This gives us the height of the yellow line. Quote Link to comment Share on other sites More sharing options...
Deby Ferdian Posted March 18, 2016 Author Share Posted March 18, 2016 (edited) Yes. That's right! I want to draw the line to be the same height as the node but in case in my situation, I stil did not know about the height so the actually what I want to know exactly is that the height without should I draw the point at the first. Oh yeah! Yes. I have post it an above before you but Do you have any ideas be simply then me! How do get the height without draw the line and points, could be such as "DIMALIGNED" or any ? How to draw the line without have to know the height first ? Edited March 18, 2016 by Deby Ferdian Be descriptively ! Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 Use the LIST command to get the Z coordinates (this will depend on the orientation of the UCS) of the two nodes and do the math. Then draw your line. Quote Link to comment Share on other sites More sharing options...
eldon Posted March 18, 2016 Share Posted March 18, 2016 Perhaps you could draw a line between the two points. When you list that line, look for the Delta Z. Quote Link to comment Share on other sites More sharing options...
ReMark Posted March 18, 2016 Share Posted March 18, 2016 Perhaps you could draw a line between the two points. When you list that line, look for the Delta Z. Yes, you can. Quote Link to comment Share on other sites More sharing options...
eldon Posted March 19, 2016 Share Posted March 19, 2016 Perhaps a simple graphical way, without looking at numbers, would be to draw a line from the point on the ridge perpendicular to the vertical line from the valley point. Take a front view and trim. Job done Quote Link to comment Share on other sites More sharing options...
Deby Ferdian Posted March 19, 2016 Author Share Posted March 19, 2016 (edited) Yes.. Alright! That's exactly what I mean.. It's greate, It's a good job, Well.. Done @eldon.. it's same with my way in advance.. I do agree with you @eldon thanks! Edited March 19, 2016 by Deby Ferdian Fix my congrats! Quote Link to comment Share on other sites More sharing options...
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