Select Polyline with variable ?

I need select a Polyline with a variable,

This code is ok!

(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "First"))))

I need convert to:

(setq cod "Second")

(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . cod))))

But this code return

Command: ; error: bad SSGET list value

I need help to make this code.

Thanks

Rodrigo

The name of the layer should be string like the first line of code you brought .

(8 . "cod")

http://www.cadtutor.net/forum/showpost.php?p=258390&postcount=20

thank you ! =)

You're welcome!

if i use

(setq valor "X1")

(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "valor"))))

The lisp does not recognize the value of the variable

If use variable with "" the lisp recognize VALOR and not X1

Any help?

if i use

 

(setq valor "X1")

(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "valor"))))

 

The lisp does not recognize the value of the variable

If use variable with "" the lisp recognize VALOR and not X1

 

Any help?

Hola .

It should like this .

(setq valor "X1")
(setq selpline (ssget "_x" [b](list[/b] '(0 . "LWPOLYLINE")([b]cons[/b] 8 valor))))

if i use

 

(setq valor "X1")

(setq selpline (ssget "_x" '((0 . "LWPOLYLINE")(8 . "valor"))))

 

The lisp does not recognize the value of the variable

If use variable with "" the lisp recognize VALOR and not X1

 

Any help?

Did you read the post I linked to?