Hi,
Is there a way of showing only the location of the xrefs using a diesel expression (or otherwise)?
At the moment I'm using $(xrefs,5), but all the xrefs are in the same folder, and I only want that folder path shown once.
I.e., even if I have 5 xrefs, I just want one line showing the fodler path of those xrefs.
Any ideas?
Cheers,
-Ifor