Draw tangent circle ?

[issammm 10]

Hi all

any can know how draw third circle between two circle if one tangent point know (fixed) (point A) and other tangent in other circle

solve this please:

Edited March 18, 2014 by issammm

[rkent 13]

circle, 3point, tan, tan, tan.

 

Start circle command, pick 3p option, type tan, enter, pick small circle, type tan, enter, pick other circle, type tan, enter, pick line.

[BIGAL 22]

Also C TTR same thing

[rkent 13]

Actually I didn't look at the image carefully but now I realize neither solution would work.

[issammm 10]

both solution incorrect, if you correct please give me Rx here.

I know tan tan tan but where i pick third tan and how can I determine tangent as point !???

[eldon 14]

It all depends on the order of picking the tan points.

 

I see that I have actually drawn the tangent line to the smaller circle, and that is one of the tan points, as well as the two circles.

[MSasu 10]

Your circle should have a radius of 9.01545790. Will post later the demonstration.

 

To draw it create an offset copy to the left circle with above value. Extend the line that join its center with desired tangent point until intersect the new circle; this is the center of the circle you were looking to draw.

 

Edit: Eldon was faster with his/her graphical solution. Nice one!

[issammm 10]

CORRECT, but still can know how you get circle tangents points ??

you look use approximation way not snap point exactly you seek cursor with vertical line and ....

 

 

can you try for me replace 5.4152 with 5.3923 ??

[eldon 14]

With the new offset, I make the new radius 9.00001399.

[issammm 10]

With the new offset, I make the new radius 9.00001399.

 

you are so closely right but still NOT get the target to answer is 9 try it in your computer and see.

 

maybe because you use 8 precision I suggest you just using 4 or two enough dear.

[eldon 14]

To get a circle of radius 9 exactly, the offset should be 5.39227909

[issammm 10]

yes my autocad just 4 precision. can you give me your way in detail you just make vertical line but how you get the second tangent point ?

[RobDraw 10]

Issammm, your original question was not stated correctly. If you had stated that the radius, Rx, was to be 9 and the offset was the variable, you would have been given a solution that was quite easy. Draw the circle with the TTR option, selecting the two circles and specifying 9 for the radius.

[issammm 10]

Issammm, your original question was not stated correctly. If you had stated that the radius, Rx, was to be 9 and the offset was the variable, you would have been given a solution that was quite easy. Draw the circle with the TTR option, selecting the two circles and specifying 9 for the radius.

 

my question is OK, eldon give me correct answers in too accurate.

jst eldon give us more precision than needed.

the Rx = 9 for case 5.3923

 

regards to all

[MSasu 10]

Issammm, I gave you above the radius, calculated as per your sketch, with 8 decimals and a solution to use it; isn't that enough for your sketch?

[RobDraw 10]

How can it be when you are changing the value, 5.4152, to a variable and assigning a value where you had a variable, Rx?

[MSasu 10]

both solution incorrect, if you correct please give me Rx here.

Seems that you were asked for the radius in the first place!

[issammm 10]

Seems that you were asked for the radius in the first place!

MSasu you are completely correct.(I hope you explain how you got your answer)

 

Rob i hope you give me correct answer next time all my replay was clear.

 

if you want more challenge draw this and find all arcs length.

[eldon 14]

It seems that there are not enough figured dimensions. For example, where is G? Is it at the end of a semicircle?

 

One could guess, but that might not be sufficiently accurate for you

[issammm 10]

It seems that there are not enough figured dimensions. For example, where is G? Is it at the end of a semicircle?

 

One could guess, but that might not be sufficiently accurate for you

points B till I are tangents points except A is a vertex, think well you will get it.