Lt Dan's legs Posted August 16, 2010 Posted August 16, 2010 don't know how to figure this out. Once I set my distance how do I subtract from it? 8" typ Quote
Michaels Posted August 16, 2010 Posted August 16, 2010 Do you mean that the line is already made and you'd like to cut 8" (8 inches) from the line ? Thanks Quote
Lt Dan's legs Posted August 16, 2010 Author Posted August 16, 2010 that is correct (defun c:example (/) (setq di (getdist)) (setq disub (- di ...;;however it needs to be worded Quote
jammie Posted August 16, 2010 Posted August 16, 2010 Would the CVUNIT function be of any help? Check out the AutoCAD developers help files for info Quote
Tharwat Posted August 16, 2010 Posted August 16, 2010 Check this link and the post #7 by Alanjt is what you looking for. http://www.cadtutor.net/forum/showthread.php?50762-Force-command-LINEor-PLine-to-jump-by-Inch-units. Regards, Tharwat Quote
Lee Mac Posted August 16, 2010 Posted August 16, 2010 I'm not sure I completely understand your question about it being worded? Quote
Lt Dan's legs Posted August 17, 2010 Author Posted August 17, 2010 I'm sorry, I have no idea why it didn't work earlier. I'll have to check what was mistyped at work what I wanted (defun c:example (/ di disub) (setq di (getdist "\nSpecify distance: ")) (setq disub (- di ) (alert (strcat "Outside dimension = " (rtos di 4) ". Inside dimension = " (rtos disub 4) ".")) (princ) ) Quote
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