cadeddie82 Posted January 3, 2011 Posted January 3, 2011 I know how to draw up a straight line in this format example: But what if its an arc, how do I do that? I have the bearing for the arc Quote
ReMark Posted January 3, 2011 Posted January 3, 2011 So you have no other information than that to work with? The arc is a simple curve is it not? If so it should have a central angle, tangent, radius and chord length (i.e. - curve data). Quote
eldon Posted January 3, 2011 Posted January 3, 2011 " Arc=45d41'30"8571 " Those figures look like no other that I have seen. The 45d41'30" looks like an angle, and I would assume it to be the central angle, but the other figures 8571 might be a telephone number. More information required. Quote
ReMark Posted January 3, 2011 Posted January 3, 2011 I know that a line can have a bearing but an arc? I'll have to dig out my surveying book; it's been a while. Quote
BIGAL Posted January 4, 2011 Posted January 4, 2011 An arc has a start and end pt does this equal the angle between them and the 8571 is the distance but your still missing the radius ! Arc S E D R Quote
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