LaLLe Posted January 17, 2011 Share Posted January 17, 2011 I´m working on a school project in which I've used a square pipe from content center and given it a radius with bend part. The problem arises when i try to make the idw drawing. Inventor wont give me the "flat pattern". I know i can calculate the true unfolded length of the pipe but it would be so much easier if inventor could straighten it in inventor. Another alternative would be a way to dimension an arc length. Hope you can help, none of my teachers can Quote Link to comment Share on other sites More sharing options...
JD Mather Posted January 17, 2011 Share Posted January 17, 2011 Zip and attach the file here. Quote Link to comment Share on other sites More sharing options...
LaLLe Posted January 17, 2011 Author Share Posted January 17, 2011 Which file. The idw or the ipt Quote Link to comment Share on other sites More sharing options...
LaLLe Posted January 17, 2011 Author Share Posted January 17, 2011 Here is the ipt. 60 x 60 x 2 - 3866 mm bue.zip Quote Link to comment Share on other sites More sharing options...
kencaz Posted January 18, 2011 Share Posted January 18, 2011 I would not bother trying to flatten that unless you had holes or slots to cut. It's just a matter of the arc length... Select the line in your idw, right click select dim type "arc length" KC Quote Link to comment Share on other sites More sharing options...
LaLLe Posted January 18, 2011 Author Share Posted January 18, 2011 Thanks for the help but as you see there are holes in the pipe. Quote Link to comment Share on other sites More sharing options...
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