nbaryosef Posted October 12, 2008 Share Posted October 12, 2008 How do i draw line at specific angle. if i have the length on the x axis and angle, when i do @.25 i need the x dim to be .25 @ 45 degrees. as shown in the picture Quote Link to comment Share on other sites More sharing options...
nocturne00 Posted October 12, 2008 Share Posted October 12, 2008 dont type @, just .25 Quote Link to comment Share on other sites More sharing options...
nbaryosef Posted October 12, 2008 Author Share Posted October 12, 2008 it wont accept @,.25 i need the x dim to be .25 not the angular line Quote Link to comment Share on other sites More sharing options...
nocturne00 Posted October 12, 2008 Share Posted October 12, 2008 i mean dont include the @ just the .25 Quote Link to comment Share on other sites More sharing options...
nocturne00 Posted October 12, 2008 Share Posted October 12, 2008 Check out the command line, the @ is automatically inputed anyway Quote Link to comment Share on other sites More sharing options...
nbaryosef Posted October 12, 2008 Author Share Posted October 12, 2008 first when i type .25 second it will come absolute style and third i need the .25 to be the x dim not the angular dim (v). when i write it the way you said i get the (V) dim as .25 i need the x dim to be .25 Quote Link to comment Share on other sites More sharing options...
nocturne00 Posted October 12, 2008 Share Posted October 12, 2008 "first when i type .25 it is placed automatically after you hit enter, see the command line in my previous post. as for your elusive question, its like drawing a right triangle where you want to draw a line(hypotenuse) where your input is based from the base angle and base length. No, there is no such way. Quote Link to comment Share on other sites More sharing options...
the ber Posted October 12, 2008 Share Posted October 12, 2008 you may have to input using rectangular (cartesian) coordinates instead of polar, because when you use polar input, autocad interprets the first number as length, and not the x-component of the length. if you want to use relative coordinates by default, with the @ symbol, then right-click on the "DYN" button and select settings. under "enable pointer input" select "settings", and then click on "relative coordinates". Quote Link to comment Share on other sites More sharing options...
eldon Posted October 12, 2008 Share Posted October 12, 2008 In this particular case, knowing that 45° gives an equal x and y dimension, you should enter a relative coordinate of 0.25,0.25. For polar coordinates, you should be inputting the hypotenuse (in this case 0.354), if you want to specify an angle. Quote Link to comment Share on other sites More sharing options...
nbaryosef Posted October 12, 2008 Author Share Posted October 12, 2008 so there is no other way of doing it, the drawing i got had only the .25 dim and the angle. so what you tell me is that i need to find the other hight dim or find out the the length of the hypotenuse (v) dim thnks Quote Link to comment Share on other sites More sharing options...
eldon Posted October 12, 2008 Share Posted October 12, 2008 If you are only given the x dimension and an angle, then you can always construct the required length. You cannot enter it directly Quote Link to comment Share on other sites More sharing options...
SuperCAD Posted October 12, 2008 Share Posted October 12, 2008 What about drawing two lines at a 90 degree angle and then using the Chamfer option? Just hit the button and type D for distance and then set Distance 1 to 0.25. Distance 2 should automatically be set to 0.25 as well, but you can change it to be any other dimension you like. Quote Link to comment Share on other sites More sharing options...
honestbud Posted January 26, 2010 Share Posted January 26, 2010 i searched for "drawing a line with specific angle" and then if found this pages.i read this 2 pages. What about drawing two lines at a 90 degree angle and then using the Chamfer option? Just hit the button and type D for distance and then set Distance 1 to 0.25. Distance 2 should automatically be set to 0.25 as well, but you can change it to be any other dimension you like. chamber is best chois for drawing a line at specific angle WHEN you already have 2 object. but sometimes you start drawing in blank screen.you need to draw a line with X distant and angle. i prefer to draw line and then ROTATE it. dose anybody have any practical solution? Quote Link to comment Share on other sites More sharing options...
Tankman Posted January 26, 2010 Share Posted January 26, 2010 Eldon, back to trig! TANKS for the reminder. :wink: The "Cheesehead" has a better idea. What happened to the Vikings? Quote Link to comment Share on other sites More sharing options...
nyd Posted January 14, 2013 Share Posted January 14, 2013 you can always use some inline lisp. This should work: l[enter] x,y[enter] (/ dx (sin (* angle (/ pi 180))))[enter] where x,y are the coordinates of the firs point dx is the desired dimension on x axis angle is the desired angle To answer the question: (/ 0.25 (sin (* 45 (/ pi 180)))) Quote Link to comment Share on other sites More sharing options...
MSasu Posted January 14, 2013 Share Posted January 14, 2013 Nyd, I believe that you should use Cosine instead of Sine trigonometric function - although it works for your case since the angle is 45 degrees. Quote Link to comment Share on other sites More sharing options...
iainlines Posted January 14, 2013 Share Posted January 14, 2013 Draw a line 0.25 in X axis, draw a line straight up from this longer than needed. Then go back to your starting point and use That said, chamfer is really the best and easiest way Quote Link to comment Share on other sites More sharing options...
JD Mather Posted January 14, 2013 Share Posted January 14, 2013 Chamfer is easiest. Next best way might be to Offset .25 or with Otracking draw vertical line, select the line, get rotation grip and rotate and trim as needed or polar tracking and trim or xline or ray ...........so many ways that will work even when not 45° Quote Link to comment Share on other sites More sharing options...
SLW210 Posted January 14, 2013 Share Posted January 14, 2013 Hopefully the OP has figured this out in the last 4 1/2 years. Quote Link to comment Share on other sites More sharing options...
iainlines Posted January 14, 2013 Share Posted January 14, 2013 That's the second time I've done something like that. I think it was 9 years last time. I feel slightly less silly as JDM was also caught out. D'oh! Quote Link to comment Share on other sites More sharing options...
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