salman Posted March 12, 2010 Share Posted March 12, 2010 I often need to draw a circle using tan,tan,radius option. After I pick the tangent points on the target lines I do not know what should be the exact value of the radius so that the circle created touches the two lines exactly at the points that were picked using the TANGENT osnap. So sometimes the circle is too small that I need to extend the two lines to meet the circle, which changes their size. Sometimes radius is too large the circle to be created. Is their some easy way using which we can find the radius required so that the circle touches the two lines at the picked points. Thanks. Quote Link to comment Share on other sites More sharing options...
eldon Posted March 12, 2010 Share Posted March 12, 2010 Is their some easy way using which we can find the radius required so that the circle touches the two lines at the picked points. Yes, by using some construction lines. Draw a perpendicular from each of your points. Where they intersect is the centre of the circle. Quote Link to comment Share on other sites More sharing options...
CarlB Posted March 12, 2010 Share Posted March 12, 2010 Or use the "3 point" option of drawing a circle. You still pick "tan" & "tan" for 2 of the points; for the third point pick a point the circle will pass through. Quote Link to comment Share on other sites More sharing options...
merdrignac Posted March 15, 2010 Share Posted March 15, 2010 You could try using "ARC start, end, direction" First fillet the two lines with zero radius. Then using the apex created as centre, draw a circle to the correct tangent point. Using "ARC start, end , direction", pick one tangent point, then pick the other tangent point, then pick the apex. Trim the apex. Hey presto!! Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.