FazBear Posted May 19, 2009 Share Posted May 19, 2009 Hi All Is it possible to control multiple commands from a single if statement? ie. (if (or (= [var1] T) (= [var2] T) (= [var3] T)) (command "circle" "0,0" "25") (command "circle" "0,0" "50") (command "circle" "0,0" "75") (command "circle" "0,0" "100") (command "circle" "0,0" "125") (command "circle" "0,0" "150") (command "circle" "0,0" "175") (command "circle" "0,0" "200") (command "circle" "0,0" "225") (command "circle" "0,0" "250") );end if I have had a play with the (cons & (cond assuming these are allowing the above but cant get it running properly. Can anyone please advise? Thank you. Quote Link to comment Share on other sites More sharing options...
wizman Posted May 19, 2009 Share Posted May 19, 2009 wrap with progn, if any of the expression is true then the whole progn statement executes. (if (or (= [var1] T) (= [var2] T) (= [var3] T)) (progn (command "circle" "0,0" "25") (command "circle" "0,0" "50") (command "circle" "0,0" "75") (command "circle" "0,0" "100") (command "circle" "0,0" "125") (command "circle" "0,0" "150") (command "circle" "0,0" "175") (command "circle" "0,0" "200") (command "circle" "0,0" "225") (command "circle" "0,0" "250") ) ) Quote Link to comment Share on other sites More sharing options...
Freerefill Posted May 19, 2009 Share Posted May 19, 2009 Ah, common mistake, I screw it up myself all the time. The structure of the If statement is: (if then else ) Ignoring the italicized text, of course. You'll notice one very important and key aspect: it only allows one command. Using a Condition statement will allow many commands, but If allows only one. You can get around this, however. Encase all your commands in a Progn, like such: (progn <command one> <command two> ... <command banana> ) Quote Link to comment Share on other sites More sharing options...
Lee Mac Posted May 19, 2009 Share Posted May 19, 2009 Progn is correct for wrapping multiple expressions, I believe you may be able to get around it like this however: (if (or [var1] [var2] [var3]) (command "circle" "0,0" "25" "circle" "0,0" "50" "circle" "0,0" "75" "circle" "0,0" "100""circle" "0,0" "125""circle" "0,0" "150" "circle" "0,0" "175""circle" "0,0" "200""circle" "0,0" "225" "circle" "0,0" "250")) PS> You don't need to specify (= [var1] T) If [var1] holds any value other than nil, it will return T. Quote Link to comment Share on other sites More sharing options...
Lee Mac Posted May 19, 2009 Share Posted May 19, 2009 Some more help on Progn here http://www.cadtutor.net/forum/showpost.php?p=173196&postcount=10 Quote Link to comment Share on other sites More sharing options...
FazBear Posted May 20, 2009 Author Share Posted May 20, 2009 Magic Thank you guys. Quote Link to comment Share on other sites More sharing options...
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