IronHorse Posted December 4, 2013 Share Posted December 4, 2013 I need to do a stress analyze of one brick from our production. I have made the brick placed It on the floor and added one pin under one segment. I need to understand what stress this will make on the object by only It´s own weight. Can someone help me with this task. All properties as density, tension and presssure value are allready attached to the brick properties. The pin is only 2mm in diameter, maybe the dimension need to be greater to make any affect. Force.zip Quote Link to comment Share on other sites More sharing options...
JD Mather Posted December 5, 2013 Share Posted December 5, 2013 How much force do you think you have on that brick (the problem isn't set up right either, but lets start with the force)? 1388000000N (for the Americans here that is 312,034,813.0228 lbf) Quote Link to comment Share on other sites More sharing options...
JD Mather Posted December 10, 2013 Share Posted December 10, 2013 Did you resolve this problem? Quote Link to comment Share on other sites More sharing options...
IronHorse Posted December 10, 2013 Author Share Posted December 10, 2013 Did you resolve this problem? No this is still open, I do not have necessary knowledge To finish this task. Quote Link to comment Share on other sites More sharing options...
Bishop Posted December 10, 2013 Share Posted December 10, 2013 Pressure is 64,092.888 PSI?!?! Over an area of 500.419 square inches?!?!?! I'd love to know what this brick is actually made of, if you're realistically planning to put that sort of load on it! Quote Link to comment Share on other sites More sharing options...
IronHorse Posted December 10, 2013 Author Share Posted December 10, 2013 Pressure is 64,092.888 PSI?!?! Over an area of 500.419 square inches?!?!?! I'd love to know what this brick is actually made of, if you're realistically planning to put that sort of load on it! There is no actuall pressure, only IT,s own Weight 438 kilogram Quote Link to comment Share on other sites More sharing options...
Bishop Posted December 10, 2013 Share Posted December 10, 2013 No, you've got a pressure load in there. A big #$%@#^$ pressure load. Quote Link to comment Share on other sites More sharing options...
JD Mather Posted December 10, 2013 Share Posted December 10, 2013 I will try to remember to post step-by-step instruction on how to do this analysis tomorrow. You will not need assembly - only the part - to do the analysis. Quote Link to comment Share on other sites More sharing options...
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