Brain dead - Trig call

Ok I'm brain dead today:

ab > bc form right angle

Length ab is known

Angle ac is known

Length ac (/ (distance ab) (sin ac))

My ugly 1 of the day is:

Length bc = (sqrt (- (* ac ac) (* ab ab)))

Any clue to the trig call I need to find length bc?

-David ( of the zombies )

Length bc = (* (distance ac) (cos A))

I have changed the angle variable to A

Thanks! I'll give it a try in the AM. I knew it should be simple, just couldn't bring it ti mind. Thanks again -David

cos ac=bc/ac

...oops, way too slow

OTHERS HAVE A HABIT OF ANSWERING

sin cos tan !

o/h a/h o/a

o opposite h hypot a adjacent