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Posted

Ok I'm brain dead today:

 

ab > bc form right angle

 

Length ab is known

 

Angle ac is known

 

Length ac (/ (distance ab) (sin ac))

 

My ugly 1 of the day is:

 

Length bc = (sqrt (- (* ac ac) (* ab ab)))

 

Any clue to the trig call I need to find length bc?

 

-David ( of the zombies )

TRIANGLE.GIF

Posted

Length bc = (* (distance ac) (cos A))

 

I have changed the angle variable to A

Posted

Thanks! I'll give it a try in the AM. I knew it should be simple, just couldn't bring it ti mind. Thanks again -David

Posted

OTHERS HAVE A HABIT OF ANSWERING

 

sin cos tan !

 

o/h a/h o/a

 

o opposite h hypot a adjacent

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