Drawing Circle on List Coordinate

Hello all,

Say you have a list in autocad. It is a point on the screen (10, 10, 10) and its variable name is pLL. I want to use the point as a reference for drawing a circle 0.6 to the right, and a user defined variable 'depth' minus 0.227. See the attached file for a better picture. This is what I am trying and it isn't working for some reason.

"_.circle"

(mapcar '- pLL '(-0.6 (- depth 0.227) 0))

0.125

I have also tried to extract each number from the pLL list seperatly, do the math, but am not sure how to put it back into a list to use as a mid-point for a circle.

(setq ax (- 0.6 (car pLL)))

(setq ay (- depth 0.227 (cadr pLL)))

These work to get the math done, but I need to rebuild a list and draw a circle on that coordinate.

(defun foo (pt val)
 (if (eq 3 (length pt))
   (list (car pt) (cadr pt) (+ (caddr pt) val))
 )
)

eg.

(foo '(0 0 0) -3) -> '(0 0 -3)

(defun foo (pt val)
 (if (eq 3 (length pt))
   (list (car pt) (cadr pt) (+ (caddr pt) val))
 )
)

 

eg.

(foo '(0 0 0) -3) -> '(0 0 -3)

I don't understand how I can use that for what I am doing. Would it work like this?

(defun foo (pt val)

(if (eq 3 (length pt))

(list (car pt) (cadr pt) (+ (caddr pt) val))

)

)

(foo '(pLL) - 0.6 (- fl 0.227) 0))

And it would change pLL to suit it?? Then what is the new lists name? I have never used foo before.

(foo PLL #)

# being the number you wish to add/subtract from the Z value of PLL.

Look at my original example.

Oops, I'm a 'tard - completely read your post wrong.

(defun foo (pt xyzLSt)
 (if (equal '(3 3) (mapcar 'length (list pt xyzLst)))
   (mapcar '(lambda (a b) (+ a b)) pt xyzLst)
 )
)

eg

Command: (foo '(1 1 1) '(1 2 0))
(2 3 1)

Oops, I'm a 'tard - completely read your post wrong.

 

(defun foo (pt xyzLSt)
 (if (equal '(3 3) (mapcar 'length (list pt xyzLst)))
   (mapcar '(lambda (a b) (+ a b)) pt xyzLst)
 )
)

eg

Command: (foo '(1 1 1) '(1 2 0))
(2 3 1)

Thanks,

I was gonna say that I didn't wanna change my z. But you got it. Thanks again I will try it in the morn.