CADken Posted September 30, 2007 Share Posted September 30, 2007 I need to draw an arc, this arc curves to the left, it has a radius of 85' and it's delta angle is 97 degrees... it then travels 185. I'm having a few issues, first off, the way i'm approaching this isn't right, somewhere i'm not doing this right... any pointers? Quote Link to comment Share on other sites More sharing options...
eldon Posted September 30, 2007 Share Posted September 30, 2007 I would approach this by first of all drawing the radius line of 85'. Then draw the arc using the centre, start, angle option, using the end points of the line you have just drawn for the centre and start points, and type in 97 for the angle. Then if the line of 185' is tangential, start the line command, and when it needs to know the start point, just hit 'Enter' and the line will start as a tangent to the arc. Then type in 185' for the distance. Of course you will get deluged with other ideas, so you can take your pick Quote Link to comment Share on other sites More sharing options...
CADken Posted September 30, 2007 Author Share Posted September 30, 2007 well it appears everytime i create my ARC it curves to the right and not the left... hmm, looks like i'll be experimenting more... Quote Link to comment Share on other sites More sharing options...
eldon Posted September 30, 2007 Share Posted September 30, 2007 AutoCAD always likes to draw arcs anticlockwise, so if you have the correct starting place, try putting in -97 for the angle Quote Link to comment Share on other sites More sharing options...
Guest Alan Cullen Posted September 30, 2007 Share Posted September 30, 2007 Another way is to draw a circle with R85'. Draw the first radius line to the point you want on the circle for the start pount of the arc. Then copy/rotate that line 97 degrees using the circle centre as the base point. Then use both lines to trim the circle of the unwanted bit. Delete the first line, and rotate the 2nd line 90 degrees using the new arc end point as the rotation point. Then LENGTHEN that line to 185 feet. Quote Link to comment Share on other sites More sharing options...
CADken Posted September 30, 2007 Author Share Posted September 30, 2007 Another way is to draw a circle with R85'. Draw the first radius line to the point you want on the circle for the start pount of the arc. Then copy/rotate that line 97 degrees using the circle centre as the base point. Then use both lines to trim the circle of the unwanted bit. Delete the first line, and rotate the 2nd line 90 degrees using the new arc end point as the rotation point. Then LENGTHEN that line to 185 feet. [ATTACH]2763[/ATTACH] thanks mate! Quote Link to comment Share on other sites More sharing options...
SLW210 Posted October 1, 2007 Share Posted October 1, 2007 If you want to change the direction angles are drawn.....ANGDIR is the System Variable, 0 = Counterclockwise and 1 = Clockwise Quote Link to comment Share on other sites More sharing options...
swampstomper Posted March 3, 2008 Share Posted March 3, 2008 I am confused about the delta angle. I am tryinying to transfer measurements from a survey to AutoCad. I am given 2 measurements for the sides of the lot and delta angles radiuses and arc length for the ends. The side lot line measurments are no problem, but how do I get the arcs into the drawing? Given: (4 sides starting at lower left corner working to right) Curve 1 Delta Angle 3d31'19" Radius 2360.08' Arc 145.07' Lot Line 197.1'Curve 2 Delta Angle 19d01'22" Radius 230.00' Arc 76.36' Lot Line 132.88' Can anyone assist? Thanks! swampstomper Quote Link to comment Share on other sites More sharing options...
CarlB Posted March 3, 2008 Share Posted March 3, 2008 The previous example from Alan shows you how to draw an arc of a given delta. The arc length is redundant information. But you're missing something to locate the arc-you don't have the chord bearing. You'll need more information, such as knowing if the side lot lines are radial to the arcs. If so, you could draw the initial circle knowing its center is 2360.08' from the side lot line/arc intersection, along the lot line extended. It the straight lot lines are not radial, you'll need to find more information. Quote Link to comment Share on other sites More sharing options...
angelo ramos Posted March 30, 2009 Share Posted March 30, 2009 I am currently working on a project where i am given a starting point and a counterclockwise direction and a length of a line to wrap around an existing radius of 35'.The problem i am having is everything i look up to help me requires a delta angle. This is probably easy for you guys and girls but i am stumped. the radius is 35'(existing feature), the line length is 144.32', the direction is counterclockwise. I hope someone can help me, i am six assignments away from completing my course.Thank you. Quote Link to comment Share on other sites More sharing options...
lpseifert Posted March 30, 2009 Share Posted March 30, 2009 Not sure what you're trying to do, draw an arc with a radius of 35 with an arc length of 144.32? Quote Link to comment Share on other sites More sharing options...
angelo ramos Posted March 31, 2009 Share Posted March 31, 2009 A much better description of my problem would be that I have an existing cul-de-sac with a 35' radius.I am trying to establish property lines.From my last point I am instructed to go around this radius, to create another. The only information in the instructions is the segment length of 144.32' and the counterclockwise direction. How do i find the delta angle for this problem? Do i even need the delta angle to create this segment of 144.32'? Quote Link to comment Share on other sites More sharing options...
Lee Mac Posted March 31, 2009 Share Posted March 31, 2009 If its the segment length you are after, there is a simple calculation relating segment length, radius and angle: segment = (angle/180)*pi*radius In LISP: (defun c:ark (/ ip rad seg ang) (if (and (setq ip (getpoint "\nSpecify Center of Arc: ") rad (getpoint ip "\nSpecify Start Point of Arc: ") seg (getdist rad "\nSpecify Segment Length: "))) (progn (setq ang (/ (* 180.0 seg) (* pi (distance ip rad)))) (command "_arc" "_C" ip rad "_A" ang)) (princ "\n<!> Something Specified Wrong <!>")) (princ)) Quote Link to comment Share on other sites More sharing options...
lpseifert Posted March 31, 2009 Share Posted March 31, 2009 Draw an arc using [start,Center,End] using the start point at the beginning of the lot line (35' from the center of the cul-de-sac) and the center at the center of the cul-de sac; an exact point of the end point doesn't matter. Then use the Lengthen command using the Total option to make the arc length 144.32'. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.