Newguy Posted December 16, 2015 Share Posted December 16, 2015 Hello, I am new to autocad and I need to finish an assignement for school but I don't even know where to start. If someone can do this for me and finds it easy I would really appreciate the help. The layers are as follows Axis lines - Dash dots, yellow, 0,35mm The main line - continuos, red, 0,7mm Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 (edited) Post an image of what you have so far. When is the assignment due? Edited December 16, 2015 by ReMark Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 (edited) Here is a sequence that might help. In the first four images anything that is not color red is really just temporary geometry. The last image in black and white is the final version. Some of the commands used were Line, Circle, Rectangle, Fillet, Rotate, Circle (with tan-tan-radius option; used in three locations), Trim and Copy. Look carefully at that square at the end and the lines going from corner to corner. Note that one of those lines is parallel to the long line that passes through the 40x60 rectangle in the middle of the sketch. That's important to note since the square, in my opinion, is rotated 6.8403 degrees. Edited December 16, 2015 by ReMark Quote Link to comment Share on other sites More sharing options...
RobDraw Posted December 16, 2015 Share Posted December 16, 2015 Look carefully at that square at the end and the lines going from corner to corner. Note that one of those lines is parallel to the long line that passes through the 40x60 rectangle in the middle of the sketch. That's important to note since the square is rotated 6.8403 degrees. I don't get this. I did get the same angle as you for the rotation of the square but the 40x60 rectangle is at an angle of 50 degrees from the horizontal center line.. Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 If you have a different solution please share it with us. I've only had two cups of coffee so far so I might not be firing on all cylinders yet. 3:30 a.m. comes awfully early in the morning. Don't understand why that is. Quote Link to comment Share on other sites More sharing options...
RobDraw Posted December 16, 2015 Share Posted December 16, 2015 I think you are right but your explanation is off a bit. If one of the diagonals of the square is parallel to the horizontal center line, the sides would be at the 45s. I did have to make an assumption about the line coming off of the square, though. That is either parallel to the horizontal center line of the drawing or to the square. I think that is the only bit of missing information. Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 I don't believe you have shown the square in the same orientation as depicted in the posted image by the OP. Take a closer look. It's possible that what I perceive to be a slightly askew square is a result of the way the OP created the image. That much I'll give you. The way you have shown it would definitely be much easier for a newbie to AutoCAD to construct the geometry. Quote Link to comment Share on other sites More sharing options...
RobDraw Posted December 16, 2015 Share Posted December 16, 2015 That cannot be determined from the drawing. I'm guessing on that. If it can be determined, please share. Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 The only way I can think of determining it, and obviously it would not be with 100% certainty, would be to create an image file and pull it into AutoCAD then using either the Scale with Reference option or the Align command to scale it. Now all you have to do is drop your drawing on top of it and compare. Quote Link to comment Share on other sites More sharing options...
Dadgad Posted December 16, 2015 Share Posted December 16, 2015 On the face of it, I would be inclined to agree with ReMark's interpretation, as in the original post the horizontal line clearly bisects the small square. Quote Link to comment Share on other sites More sharing options...
RobDraw Posted December 16, 2015 Share Posted December 16, 2015 Overlaying the image makes it look as if the square is at 45 degree angle to the horizontal center line. What were you referring to with this? since the square is rotated 6.8403 degrees. Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 I don't believe the square is at a 45 degree angle but it's all in the eye of the beholder. The OP can derive his own conclusions. Quote Link to comment Share on other sites More sharing options...
TheCADnoob Posted December 16, 2015 Share Posted December 16, 2015 If it was the real world and this dimension was mission critical the problem is a quality issue and requires a RFI, but given that this is for academia and they are vindictive, it is my suspicion that they are going to make it a gotcha. Judging by the use of line weight to distinguish between construction/dimension lines (.3 mm) and object lines (.6 mm) (per ASME Y14.2 since this is academia) the proper conclusion is that the diamonds vertical line is perpendicular to the center line running through the object and this is why it extends to the diamond tip. This would mean that the diamond's lower left side is not necessarily collinear with the bottom line. ... I love me some BS lol Quote Link to comment Share on other sites More sharing options...
steven-g Posted December 16, 2015 Share Posted December 16, 2015 Remark you are off by a mile, I get 6.8439° maybe the coffee is kicking in by now (and at 45°) Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 I guess I overshot the landing. Quote Link to comment Share on other sites More sharing options...
eldon Posted December 16, 2015 Share Posted December 16, 2015 I also got 6° - 50' - 38" Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 Even if the OP did it the way Robdraw depicted he would get a high score. At this point I think we are splitting hairs. Quote Link to comment Share on other sites More sharing options...
steven-g Posted December 16, 2015 Share Posted December 16, 2015 Shall we just round it up to 78) Quote Link to comment Share on other sites More sharing options...
Newguy Posted December 16, 2015 Author Share Posted December 16, 2015 Really thank you all for the contribution, really appreciate the help. That you had the time to post here and explain it step by step is just amazing. Thank you all Quote Link to comment Share on other sites More sharing options...
ReMark Posted December 16, 2015 Share Posted December 16, 2015 Well good luck with your assignment. Let us know what grade you got. Quote Link to comment Share on other sites More sharing options...
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