vanowm Posted May 26 Share Posted May 26 (edited) If we have lengths of each side of a triangle ( L1, L2, L3 ), we can draw 2 circles at a distance of L1 from each other, with radius of L2 and L3 respectively. Center of each circle would give us P1 and P2 coordinates and intersection of these circles would be the P3 point. How would we get P3 coordinates without drawing anything in autolisp if P1 and P2 are already known? (Looking for a most performance efficient way) Thank you. TLDR; Working code in this reply. Edited May 30 by vanowm Quote Link to comment Share on other sites More sharing options...
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.